Question

the 9 th and the 10 th sum

Answer 1

hope it will help uh

Answer 2

Hey friend,
Here is the answer you were looking for:
$9) \frac{2x - 1}{4} = \frac{3x + 2}{2} + 1 \\ \\ = \frac{2x - 1}{4} = \frac{3x + 2 + 1 \times 2}{2} \\ \\ = \frac{2x - 1}{4} = \frac{3x + 4}{2} \\ \\ cross \: multiplying \: we \: get \\ \\ 2(2x - 1) = 4(3x + 4) \\ \\ 4x - 2 = 12x + 16 \\ \\ = 4x - 12x = 16 + 2 \\ \\ = - 8x = 18 \\ \\ x = \frac{18}{ - 8} \\ \\ x = \frac{9}{ - 4} \\ \\ x = \frac{ - 9}{4} \\ \\ 10) \: \: \frac{x - 1}{2} + \frac{x - 2}{3} = \frac{x - 3}{4} \\ \\ taking \: lcm \: we \: get \\ \\ = \frac{x \times 3 - 1 \times 3 + x \times 2 - 2 \times 2}{6} = \frac{x - 3}{4} \\ \\ = \frac{3x - 3 + 2x - 4}{6} = \frac{x - 3}{4} \\ \\ = \frac{5x - 7}{6} = \frac{x - 3}{4} \\ \\ on \: cross \: multiplying \: we \: get \\ \\ 4(5x - 7) = 6(x - 3) \\ \\ 20x - 28 = 6x - 18 \\ \\ = 20x - 6x = - 18 + 28 \\ \\ 14x = 10 \\ \\ x = \frac{10}{14}$

Hope this helps!!!!

@Mahak24

Thanks...
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