Question

The 9th term from the end of the AP, 7, 11, 15, 147 is:
(a) 135
(b) 125
(c) 115

a=7
d=4
an⁹=147 or l=147
an⁹= a+n-1×d
147 = 7+9-1×4
147= 7 + 8×4
147= 32

147=32

147-32 =115
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Answer 1

Step-by-step explanation:

a=7

d=11-7=4

n=9

an=a+(n-1)d

a9=7+(8)4

a9=7+32

a9=39

Answer 2

Step-by-step explanation:

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