Question

The 9th term of arithmetic progression is 499 and 499th term is 9.The term which is equal to zero is
(i) 501st
(ii)502nd
(iii) 504th
(iv) none of these

Answer 1

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Answer 2

Given : The 9th term in an arithmetic series is 499 and the 499th term is 9  

To Find : which term is zero

(i) 501st

(ii)502nd

(iii) 504th

(iv) none of these

Solution:

Let say AP is

a , a + d  ,a  + 2d , . . .  .

nth term = a + (n - 1)d

9th term in an arithmetic series is 499

=> a + 8d  = 499  Eq1

499th term is 9

=> a + 498d = 9   Eq2

Eq2 - Eq2

=> 490d  = - 490

=> d = - 1

a + 8d  = 499

=>a - 8 = 499

=> a = 507

a + (n - 1)d = 0

=> 507 + (n - 1)(-1) = 0

=> 507  + 1 - n = 0

=> 508 = n

508th term is  0

none of these is correct answer

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