the A.M of first n natural numbers is
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A.M. = Sum of all terms/number of all terms
A.M. = (1+2+3+4+...........+n)/n
*Note: Sum of n natural number is (n(n+1))/2.
So, A.M. = n(n+1)/2n
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First n natural numbers are 1,2,3,.....,n.
Now we have to find the arithmetic mean of first n natural numbers. we know that the sum of n natural number is n*(n+1)/2. [We can prove this by mathematical induction method.]
Then, A.M. = sum of first n natural numbers/n
= n*(n+1)/ 2n
=(n+1)/2
Answer: Arithmetic mean of first n natural number is (n+1)/2
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