The A.P. in which 4" term is -15 and 9th term is -30. Find the 10th term
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Answered by
1
Answer:
4th term= -15
9th term = -30
then 10th term= a+9d
9th term = a+8d= -30
4th term=a+3d= -15
now
subtract both terms
5d= -15
d= -3
then a= -6 then 10th term = -6+9(-3)
-6-27
= -33
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Answered by
1
ANSWER:
- 10th term = -33
GIVEN:
- 4th term of an A.P is -15.
- 9th term of an A.P is -30.
TO FIND:
- 10th term of the A.P.
SOLUTION:
Formula:
=> nth term = a+(n-1)d
Where:
a = First term
d = Common difference.
n = number of terms.
Now :
=> 4th term = a+(4-1)d
=> -15 = a+3d
=> a+3d = -15 .....(i)
=> 9th term = a+(9-1)d
=> -30 = a+8d
=> a+8d = -30. ....(ii)
Subtracting eq (i) from (ii)
=> a+8d-a-3d = -30+15
=> 5d = -15
=> d = -15/5
=> d = -3
Putting d = -3 in eq (i)
=> a+3(-3) = -15
=> a = -15+9
=> a = -6
=> 10th term = -6+(10-1)(-3)
=> 10th term = -6+9(-3)
=> 10th term = -6-27
=> 10th term = -33
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