The a value of a function in the form f(x) = ax2 + bx + c is negative. Which statement must be true?
The vertex is a maximum.
The y-intercept is negative.
The x-intercepts are negative.
The axis of symmetry is to the left of zero.
Answers
Answer:
The axis of symmetry is to the left of zero." The a value of a function in the form f(x) = ax2 + bx + c is negative. The statement must be true is this The axis of symmetry is to the left of zero....
Answer:
Given is a standard quadratic equation of the form:
f (x) = ax ^ 2 + bx + cf(x)=ax^2 +bx+c
As the function is negative then the following is true:
Therefore, when the leading coefficient is less than one then:
1) The parable opens down.
2) The cutting points with the x axis can be positive or negative
3) The cutoff point with the y axis can be positive or negative
4) The axis of symmetry can be to the right or to the left of zero.
5) The vertex of the parabola is a maximum and this is because the second derivative is negative.
So the answer is
The vertex is a maximum.