Question

The absolute maximum bending moment in a simply supported beam of span 10m due to moving load of udl 4kn/m, spanning over 6m is

Answer 1

Answer:

The answer will be  183.33t-m

Explanation:

According to the problem span of the beam  is l

let the moment is m and w is the moving load of udl

therefore m  at max = r1 (a+ (r1/2w)).

r1 = (wb (a+c+b) /2l).  [ where a = 7.5, b = 5, c = 7.5, a+b+c = 20 ]

r1 = 20

m max = 20 (7.5+ (20/2*6)) = 183.33 t-m.

Answer 2

Answer:

Explanation:

The answer will be 183.33t-m

Explanation:

According to the problem span of the beam is l

let the moment is m and w is the moving load of udl

therefore m at max = r1 (a+ (r1/2w)).

r1 = (wb (a+c+b) /2l). [ where a = 7.5, b = 5, c = 7.5, a+b+c = 20 ]

r1 = 20

m max = 20 (7.5+ (20/2*6)) = 183.33 t-m.