Question

The angle of elevation of a cloud from a point 60m above a lake is 30 degree and angle of depression

Answer 1

Answer:

angles are 30:60: 90

sides opposits are 1: V 3:2

side against ratio I is 60

Hence Side against ratio 2 = V3x60 = 60v3 cm

60v3 cm is the distance

angle of depresion in 60°

Answer 2

Answer:

Let A be the cloud and D be its shadow.

BC = 60 m  

Height of cloud = h m .

Total height of cloud = h + 60 m  

In  Δ ABE

h / x = tan 30

x = h √ 3

In Δ BDE

h + 60 + 60 / x  = tan 60

h + 120 = x √ 3

2 h = 120

h = 60 m .

Therefore , height of cloud from surface of water = ( 60 + 60 ) = 120 m .