the absolute refractive index of water is 4/3 . What is the critical angle?
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Answered by
90
n = 1/sinC
sinC = 1/n
sinC = 1/(4/3)
sinC = 3/4
sinC = sin48.59
C = 48.59°
Critical angle is 48.59°
sinC = 1/n
sinC = 1/(4/3)
sinC = 3/4
sinC = sin48.59
C = 48.59°
Critical angle is 48.59°
Answered by
32
for an air-water boundary c = 48.5°
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