Question

the absolute refractive index of water is 4/3what is the critical angle

Answer 1

Hey mate here is your answer

N=1/sinC
SinC=1/n
SinC=1/(4/3)
SinC=3/4
SinC=sin 48.59
C= 48.59°

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Answer 2

Given, the absolute refractive index of water is said to be 4/3.

Assume, the critical angle is said to b C. Stating, Snell’s Law, C is equal to sin^-1(1 divided by refractive index) C is equal to sin^-1(3 divided by 4) C is equal sin^-1(0.75) C is equal 48.59°

Answer 3

Given, the absolute refractive index of water is said to be 4/3.

Assume, the critical angle is said to b C. Stating, Snell’s Law, C is equal to sin^-1(1 divided by refractive index) C is equal to sin^-1(3 divided by 4) C is equal sin^-1(0.75) C is equal 48.59°