Question

the acceleration a in m/s^2 of a particle is given by a=3t^2+2t+2,where t is the time.if the particle starts out with a velocity v=2m/s at t=0,then the velocity at the end of 2s is

Answer 1

a=(v-u) /t
3×2×2+2×2+2=(v-2)/2
=>12+4+2=(v-2)/2
=>v-2=18x2
=>v=38m/s.

Hope this will help you.

If you like my answer
Please mark it as brainliest And
Be my follower if possible.