the acceleration 'a' of a particle is given by a=2t 2 +3t+5 where t is the time. if the velocity of the particle at t=0 was 2m/s then calculate the velocity at t=3s.
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accelaration is change in velocity per time
v= u+ a×t
a at t=3 is a= 2×3×3+3×3+5
32m/s2
v= 2+32×3=98m/s2
v= u+ a×t
a at t=3 is a= 2×3×3+3×3+5
32m/s2
v= 2+32×3=98m/s2
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Answer:
29 m/s¹
Explanation:
a=2t^2+3t+5
Now integrate it , we will get
Vf - Vi = 2 t³/3 + 3 t² + 0
Vf-2 = 4t³ + 6t² +0 / 6
Velocity at t=3 sec
6Vf-12 = 4(27) + 6(9)
6Vf = 108+54+12
6Vf = 174
Vf = 29 m/s
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