Physics, asked by VIBHsheenashiknore, 1 year ago

the acceleration 'a' of a particle is given by a=2t 2 +3t+5 where t is the time. if the velocity of the particle at t=0 was 2m/s then calculate the velocity at t=3s.

Answers

Answered by aashi14
2
accelaration is change in velocity per time
v= u+ a×t
a at t=3 is a= 2×3×3+3×3+5
32m/s2
v= 2+32×3=98m/s2
Answered by namanverma442
0

Answer:

29 m/s¹

Explanation:

a=2t^2+3t+5

Now integrate it , we will get

Vf - Vi = 2 t³/3 + 3 t² + 0

Vf-2 = 4t³ + 6t² +0 / 6

Velocity at t=3 sec

6Vf-12 = 4(27) + 6(9)

6Vf = 108+54+12

6Vf = 174

Vf = 29 m/s

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