the acceleration due to gravity, at a depth d below the surface of earth,equal gravity at depth.obtained the formula for the ratio (gd /ge) where ge is the acceleration due to gravity on the surface of the earth
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Hey buddy,
● Answer -
gd/ge = 1 - d/R
● Explanation -
[Refer to image for figure.]
Let gd be acceleration due gravity at depth d from surface.
gd = (4/3) πG(R-d) / ρ
Also ge be acceleration due to gravity at earth surface -
ge = (4/3) πGR / ρ
Taking ratio of gd/ge -
gd/ge = [(4/3)πG(R-d)/ρ] / [(4/3)πG(R-d)/ρ]
gd/ge = (R-d)/R
gd/ge = 1 - d/R
Hope thiz helped...
● Answer -
gd/ge = 1 - d/R
● Explanation -
[Refer to image for figure.]
Let gd be acceleration due gravity at depth d from surface.
gd = (4/3) πG(R-d) / ρ
Also ge be acceleration due to gravity at earth surface -
ge = (4/3) πGR / ρ
Taking ratio of gd/ge -
gd/ge = [(4/3)πG(R-d)/ρ] / [(4/3)πG(R-d)/ρ]
gd/ge = (R-d)/R
gd/ge = 1 - d/R
Hope thiz helped...
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