Two identical resistors of 12 ohm are connected to a voltmeter of 3v. Find the ratio of the power consumed by them when resistance is minimum and maximum
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Ohms Law: V=IR
[20/(6+4)=current]×[6=resistance]= Answer: 12 volts
Check: If the 6 Ohm resistor has a 12v drop, and the total “potential difference” is 20v, then the 4 Ohm resistor should have 8v across it, right? >>> [20/(6+4)]×4= 8v…
8v=8v Yep, correct!
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12 volts is the correct answer to your question dear.
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