Physics, asked by shirisha1501gowda, 15 hours ago

The acceleration of a body starting from rest varies with time
following the equation a = 3t + 4, where a is in ms-2 and t in s. The
velocity of body at t = 2 s will be
18 m/s
14 m/s
12 m/s
20 m/s​

Answers

Answered by jaspreet852870
1

Answer:

eq.for acceleration= 3t+4

put t= 2 sec

a= 3×2+4

a= 10 ms-²

Now using using eq v= u+ at

u = 0( initially body was at rest)

v = 0+10×2

v= 20ms-¹

Explanation:

so.. option d is correct 20m/s

hope it helps you

Thank you

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