Question

The acceleration of a free fall on a particular palnet is 6m/ s2. An object is dropped from a hieght and hits the ground after 1 s. From what height was it dropped?​

Answer 1

Answer:

• 3m

Explanation:

$\underline{\sf{\purple{\:\:\:Given :-\:\:\:\:}}}$

• The acceleration of a free fall on a particular palnet is 6m/s².
• An object is dropped from a hieght and hits the ground after 1s.

$\underline{\sf{\purple{\:\:\:\:To\:Find :-\:\:\:\:}}}$

• From what height was it dropped

$\underline{\sf{\purple{\:\: Calculation :-\:\:\:\:}}}$

v = u + at

where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time taken

→ v = 0 + 6 × 1

→ v = 6 × 1

→ v = 6 m/s

v² - u² = 2as

where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• s = Displacement

→ 6² - 0² = 2 × 6s

→ 6² - 0 = 12s

→ 36 = 12s

→ s = $\frac{36}{12}$

→ s = 3 m

❥ Height which the object is dropped is 3m

Answer 2

$\pink{\underline{\underline{\purple{Answer:-}}}}$

v = u + at

where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time taken

→ v = 0 + 6 × 1

→ v = 6 × 1

→ v = 6 m/s

v² - u² = 2as

where,

v = Final velocity

u = Initial velocity

a = Acceleration

s = Displacement

→ 6² - 0² = 2 × 6s

→6² - 0 = 12s

→ 36 = 12s

→ s = $\frac{3}{12}$

→s = 3 m

hope it helps ☺️❤️