Question

The acceleration of a particle starting from rest is given by a=bt2+ct. Where b and c are constants. Show that velocity is bt3/3+ct2/2​

Answer 1

Explanation:

There is a rule that if we integrate acceleration we get velocity and on integrating velocity we get distance.

So on integrating acceleration we get:

bt^3÷3+ct^2÷2

We get this result because there is a rule that x^n=x^n+1÷n+1.(Integration of x)

So we get that result.