Question

The acceleration of gravity is given as a function of elevation above sea level by g = 980.6 - 3.086 * 10 ^ - 6 * H If where g is in cm/s², and H is in cm. If an aeroplane weighs 90,000 N at sea level, what is the gravity force upon it at 10,000 m elevation? What is the percentage difference from the sea-level weight?​

Answer 1

In the reading text 'Attitude is Altitude' , you have read about Nick's disability. After he was born, his parents were worried about his future. They decided to make him independent despite his disability. Now, write a possible conversation between Nick's parents. You may use the following ideas; @shocked to an abnormal @ cursed their fate @decided to grow him up to live independently. OR 21. (B)Write a letter to you friend describing how you spent your days at home during lock down ,covid-19 pandemic.

Answer 2

The difference percentage from the sea-level $0.3147$%(less).

Explanation:

$g=980.6-3.086*10^{-6}*10,000*100$

$=977.514\frac{cm}{s^{2}}$

$=9.77514\frac{m}{s^{2}}$

$W_{sea} =90,000N$

$=\frac{90,000}{9.806} kgf$

$=9178.054 kgf$

$W_{ete}=9178.054*9.77514 N$

$=89716.765 N$

%$less$ =$\frac{90,000-89716.765}{90,000} *100$%

$=0.3147$%(less).

Therefore, the difference percentage from the sea-level weight 0.3147%(less).