Question

The acceleration(s) of block of 2 kg
cannot be
2 kg
→ u = 0.4
3 kg
→FPO)
smooth​

Answer 1

Explanation:

masses=2kg,4kg 

Coefficient 0.20

Force =12N

R1−2g=0

R1=2x10=20

2a+0.2R1−12=0

2a+0.2(20)=12

2a=12−4

a=4m/.s2

Again, 

4a−μR1=0.2(20)=4

a1=1m/s2