Question

The accl.due to gravity at a point on the surface of earth is 9.8 m/s2 on going down 6.4 km below thw surface the accel due to gravity will bw

Answer 1

❣️$\huge\underline\mathfrak{heya}$❣️

We have g=Gm/R²

Let the value of g at a hight equal to the radius of earth is g”

Then, g”=Gm/(2R) ²

g"=Gm/4R²

So, g"=g/4

g"=9.8/4

=2.45m/s² (answer)

✔️hope it helps☺️