The accl.due to gravity at a point on the surface of earth is 9.8 m/s2 on going down 6.4 km below thw surface the accel due to gravity will bw
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We have g=Gm/R²
Let the value of g at a hight equal to the radius of earth is g”
Then, g”=Gm/(2R) ²
g"=Gm/4R²
So, g"=g/4
g"=9.8/4
=2.45m/s² (answer)
✔️hope it helps☺️
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