Question

the action of zn,fe,cu & al metal on the following salt solutions. (i) znso4(aq) (ii)cuso4. (iii)FeSo4(aq) (iv)Al2(So4)3(aq)​

Answer 1

Answer:

Zinc CuSO4 Blue color of CuSO4 disappears and red-brown copper particles settle down at the bottom of the beaker. Changes Zn can displace Cu from CuSO4 solution.

Zn + CuSO4 ---> ZnSO4 + Cu

 Al2(SO4)3 Solution remains colorless. No change Zn cannot displace Al from Al2(SO4)3 solution.

 FeSO4 Green colour of ferrous sulphate disappears. Iron metal is settling down at the bottom of the beaker. Changes Zn can displace Fe from FeSO4 solution.

Zn + FeSO4 ---> ZnSO4 + Fe

Copper ZnSO4 Solution remains colorless. No change Cu cannot displace Zn from ZnSO4 solution.

 Al2(SO4)3 Solution remains colorless. No change Cu cannot displace Al from Al2(SO4)3  solution.

 FeSO4 Solution remains colorless. No change Cu cannot displace Fe from FeSO4  solution.

Aluminium ZnSO4 Solution remains colorless. Zinc metal is settling down at the bottom of the beaker. Changes Al can displace Zn from ZnSO4 solution.

2Al + 3ZnSO4  ---> 3Zn + Al2(SO4)3

 CuSO4 Blue colour of CuSO4 disappears. The   brown colored copper particles settle down at the bottom of the beaker. Changes Al can displace Cu from CuSO4 solution.

2Al + 3CuSO4 ---> 3Cu + Al2(SO4)3

 FeSO4 Green colour of FeSO4 disappears. Iron   metal is settling down at the bottom of the beaker. Changes Al can displace Fe from FeSO4 solution.

2Al + 3FeSO4---> 3Fe + Al2(SO4)3

 

Iron ZnSO4 Solution remains colorless. No change Fe cannot displace Zn from ZnSO4  solution

 CuSO4 Blue colour of CuSO4 changes to light green colored FeSO4. Copper metal is formed in the beaker. Changes Fe can displace Cu from CuSO4 solution.

Fe+ CuSO4  ---->    Cu +  FeSO4

 Al2(SO4)3 Solution remains colorless. No change Fe cannot displace Al from Al2(SO4)3  solution.

Explanation:

Answer 2

Answer:

Explanation:

Check attached table below