Question

the activation energy for a reaction is 209.5 kj mol per second at 518K .calculate the fraction of molecules of reactant having energy equal to or greater than activattion energy?

Answer 1

Answer:

In the given case:

Ea = 209.5 kJ mol - 1 = 209500 J mol - 1

T = 581 K

R = 8.314 JK - 1 mol - 1

Now, the fraction of molecules of reactants having energy equal to or greater than activation energy is given as