The actually answer is 11. What am I doing wrong?
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Answered by
1
your ans
the process is as follows
x-3=0
x=3
4x2+kx-1=2
put values
4×9+k×3-1=2
36+3k=3
3k=-33
k=-11
the process is as follows
x-3=0
x=3
4x2+kx-1=2
put values
4×9+k×3-1=2
36+3k=3
3k=-33
k=-11
U transposed wrong
my teacher said its 11
Bro if u take k on the other side, then it would bcom negative
Yes
He has written 11
Ok
Mine was already correct
can u stop comenting?!
Answered by
3
Lets see.. ATQ: u have to put the value of 3 in the place of x and equate it with 2 4*9 +3x-1=2 36 -1-2=-3x 33= -3x x= -11 Answer is -11 We are substitutin gthe value of 3 as it is given that x-3 on dividing gives 2
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