the acute angle between the lines x-y=0 and y=0 is
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line y = 0 is X-axis slope of this line = 0 = m1
line x-y = 0 is y = x which is passes through (0,0) slope of this line = 45 = m2
tanФ = (m2-m1)/(1-m1m2) = (1-0)/(1-1*0)
= 1/1 = 1
tanФ =1
Ф = 45
line x-y = 0 is y = x which is passes through (0,0) slope of this line = 45 = m2
tanФ = (m2-m1)/(1-m1m2) = (1-0)/(1-1*0)
= 1/1 = 1
tanФ =1
Ф = 45
bkritagya:
thnks
Answered by
3
Step-by-step explanation:
there is one more method
M1=-1 @=135
M2=0
so angle between them
180-135
which is 45
may it helps
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