the acute angles of a right triangle are in the ratio of 4:5 find the angles of a triangle
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Answered by
14
Solutions :
In the right angled triangle,
Its one angle is 90°
And the sum of all angles of a triangle is equal to 180°
So, other two angles = (180 - 90) = 90°
Now,
Let the two acute of the triangle be 4x and 5x
A/q
=> 4x + 5x = 90
=> 9x = 90
=> x = 90/9 = 10
Hence,
The first acute angle = 4x = 4 × 10 = 40°
The second acute angle = 5x = 5 × 10 = 50°
In the right angled triangle,
Its one angle is 90°
And the sum of all angles of a triangle is equal to 180°
So, other two angles = (180 - 90) = 90°
Now,
Let the two acute of the triangle be 4x and 5x
A/q
=> 4x + 5x = 90
=> 9x = 90
=> x = 90/9 = 10
Hence,
The first acute angle = 4x = 4 × 10 = 40°
The second acute angle = 5x = 5 × 10 = 50°
Answered by
5
Let acute angle one get and another angle be x and y
4x+5x =90°
9x = 90°
x = 10°
Put the value of x in 4x&5x.
And third angle be 90°
4x = 10*4 =40°
5x = 10*5 = 50°
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