Question

The addition of a number three fourth of the number half of the number and one eleventh of the number is 618 find the number

Answer 1

Answer:

$Required \: number = 264$

Step-by-step explanation:

$Let \: a \: number\: be \: x$

$Three \: fourth \: the \: number = \frac{3x}{4}$

$Half \: of \: the \: number = \frac{x}{2}$

$One \: elevanth \: of \: the \: number =\frac{x}{11}$

/* According to the problem given,

$x +\frac{3x}{4}+\frac{x}{2}+\frac{x}{11}= 618$

$\implies \frac{44x+33x+22x+4x}{44}= 618$

$\implies \frac{103x}{44}=618$

$\implies x =618 \times \frac{44}{103}$

$\implies x = 6 \times 44= 264$

Therefore,.

$Required \: number = x = 264$

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Answer 2

Answer:

Step-by-step explanation: