The addition of HBr to 1-butene gives a mixture of products
A, B and C.
(C) CH₃ -CH₂ -CH₂ -CH₂ -Br
The mixture consists of
(a) A and B as major and C as minor products
(b) B as major, A and C as minor products
(c) B as minor, A and C as major products
(d) A and B as minor and C as major products
Answers
Answered by
0
Answer:
hey mate d. is ur answer
Answered by
0
A and B as major and C as minor products will be formed.
Explanation:
- The addition of HBr to 1 butene is a classical example of Markonikoff addition.
- The markonikoff addition leads to the formation of a chiral carbon and it forms the selective products.
- The markonikoff addition leads to formation of 2 bromobutane as the product.
- So A and B will be produced in major amounts.
- There will be antiMarkonikoff addition as well which will form the product C i.e 1bromobutane.
For more information about Markonikoff addition,
https://brainly.in/question/2340520
Anti markovnikov addition of hbr is not observed in which of following (a) propene (b) but-i-ene (c)but-2-ene (d) pent-2- Ene
https://brainly.in/question/9005176
mechanism of markovnikov and anti markovnikov rule - Brainly.in
Similar questions