the adjacent angle of parallelogram are ( 3x - 12) and (52 + 2x) . find the angle of parallelogram
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(3x-12)+(2x+52)=180
5x+52-12=180
5x+40=180
5x=180-40
5x=140
x=140/5
x=28
(3×28-12)=72°
(2×28+52)=108°
5x+52-12=180
5x+40=180
5x=180-40
5x=140
x=140/5
x=28
(3×28-12)=72°
(2×28+52)=108°
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1
l hope its heLp u.....
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anu520:
sorry this is wrong I wrote 126
116
not 126
what
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