Question

the adjacent angles of a parallelogram (4x-7) and (6x-3) find the angles of parallelogram

Answer 1

Hi,.

We know that opposite side of parallelogram are parallel..

The sum measure of adjacent angles of parallelogram is 180

4x-7+6x-3=180

10x-10=180

10x=190

x=19

4x-7=19*4-7
=76-7
=69

6x-3=6*19-3
=114-3
=111

Answer 2

Sum of adjacent angles of a llgm is 180°
So, A/q
(4x-7) + (6x-3) = 180°
10x - 10 = 180°
x - 1 = 18°
x = 19°
Therefore, (4x - 7) = 4X19-7 = 76-7 = 69°.
And, (6x-3) = 6X19-3 = 114- 3 = 111°.
Hence, angles are 69°, 111°, 69°, 111°.