The adjacent angles of a parallelogram are (3x - 12) degree and (52 + 2x)degree.Find the angles of the parallelogram?
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Answered by
10
Heya ✋
Let see your answer !!!!!
We know that the sum of the angles of a parallelogram is equal to 360°.
Opposite angles of parallelogram are equal.
Solution
2(3x - 12 + 52 + 2x) = 360
=> 2(5x + 40) = 360
=> 5x + 40 = 360/2
=> 5x + 40 = 180
=> 5x = 180 - 40
=> 5x = 140
=> x = 140/5
=> x = 28
Hence , 1st angle = (3 × 28 - 12)°
= (84 - 12)°
= 72°
2nd angle = (52 + 2 × 28)°
= (52 + 56)°
= 108°
3rd angle = 72° [opposite angles of parallelogram are equal]
4th angle = 108° [opposite angles of parallelogram are equal].
Thanks :))))))
Let see your answer !!!!!
We know that the sum of the angles of a parallelogram is equal to 360°.
Opposite angles of parallelogram are equal.
Solution
2(3x - 12 + 52 + 2x) = 360
=> 2(5x + 40) = 360
=> 5x + 40 = 360/2
=> 5x + 40 = 180
=> 5x = 180 - 40
=> 5x = 140
=> x = 140/5
=> x = 28
Hence , 1st angle = (3 × 28 - 12)°
= (84 - 12)°
= 72°
2nd angle = (52 + 2 × 28)°
= (52 + 56)°
= 108°
3rd angle = 72° [opposite angles of parallelogram are equal]
4th angle = 108° [opposite angles of parallelogram are equal].
Thanks :))))))
Answered by
0
As we know what adjacent angles are equal to 180°
According to the question :
➡ (2x - 12)° + (52 + 3x)° = 180°
➡ 2x - 12 + 52 + 3x = 180
➡ x + 40 = 180
➡ x = 180 - 40
➡ x = 140°
Therefore
The angles are :
➡(2x - 12)° = 72°
➡(52 - 3x)° = 108°
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