the adjacent angles of a Trapezium ABCD in which ab parallel to CD are 2 X + 50 and 2x - 10 find the measures of the angles
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In a Trapezium, the adjacent angles are supplementary.
Hence, 4x + 40 = 180°
x = 35°
Angle ADC = 60° = Angle ABC
Angle DAC = 120° = Angle DCB
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Answered by
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Answer:
2x + 50 + 2x-10=180
4x +40=180
4x=140
x=35
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