the adjacent sides of a parallelogram ABCD are AB = 34 cm, BC = 20cm and diagonal AC = 42cm. find the area of the parallelogram
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Answered by
184
AB = 34 cm BC = 20 cm AC = 42 cm
s = (34+20+42)/2 = 48 cm
Area of triangle ABC
= √[s (s-a) (s-b)(s-c) ]
= 6 * 4 * 14 cm²
Area of parallelogram is twice the area of triangle ABC.
s = (34+20+42)/2 = 48 cm
Area of triangle ABC
= √[s (s-a) (s-b)(s-c) ]
= 6 * 4 * 14 cm²
Area of parallelogram is twice the area of triangle ABC.
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Answered by
246
consider the triangle ABC
AB=34
BC=20
CA=42
=>S=(34+20+42)/2
=48
remember that area of a triangle=√s(s-a)(s-b)(s-c)
=√48*14*28*6
=336cm²
area of parallelogram=2*336=672cm²
AB=34
BC=20
CA=42
=>S=(34+20+42)/2
=48
remember that area of a triangle=√s(s-a)(s-b)(s-c)
=√48*14*28*6
=336cm²
area of parallelogram=2*336=672cm²
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