Question

The adjacent sides of a parallelogram are 5cm and 8 cm if the distance between two longer sides is 4 cm find the different between the shorter sides

Answer 1

Answer:

Opposits sides of parallelogram are equal so difference between them is zero...

Answer 2

$\bf{\huge{\underline{\boxed{\sf\purple{Answer:6.4\:cm}}}}}$

$\huge\underline{\tt Explanation:}$

$\sf\green{\underline{Given:}}$

• Adjacent sides of parallelogram are - 5 cm and 8 cm, largest side = 8 cm, smaller side = 5 cm.
• Distance ( height ) between two longer sides is 4 cm.

$\sf\blue{\underline{To\:Find:}}$

• The difference between the shorter sides.

$\textsf{\underline{\large{Solution:}}}$

As we know, distance between two sides = height.

→ Distance between two larger sides is 4 cm. It means, height = 4 cm.

∵ Area of parallelogram = base × height

So,

Base = larger side ( in this case )

= 8 × 4

= 32 cm²

Now,

For shorter sides,

Area of parallelogram = base ( smaller side ) × height ( distance between them )

⇒ 32 = 5 × height

⇒ $height =\dfrac{32}{5}$

∴ height = 6.4 cm.

Answer :

The distance between the shorter sides is 6.4 cm.

$\rule{200}2$