The adjacent sides of a parallelogram are in the ratio 3:7 and the perimeter
Is 100cm. Find the sides of the parallelogram.
Answers
[ REFER TO THE ATTACHMENT ]
Here, given that
- Adjacent sides of a parallelogram are in the ratio 3 : 7.
- Perimeter of the parallelogram is 100cm.
Put k in the ratio of the adjacent sides of the parallelogram.
- First side = BC = 3k
- Second side = AB = 7k
Let
- BC = a
- AB = b
As we know that perimeter of a parallelogram is 2 (a + b)
Now, according to question :
➥ 2 (3k + 7k) = 100
➥ 2 (10k) = 100
➥ 20k = 100
➥ k = 100/20
➥ k = 5
Put the value of k in the ratio.
- First side = BC = AD = 3k = 3(5) = 15 units
- Second side = AB = CD = 7k = 7(5) = 35 units
[ Since, opposite sides of a parallelogram are equal, So, BC = AD and AB = CD ]
Hence,all sides of the parallelogram are 15 units, 35 units, 15 units and 35 units respectively.
Q) The adjacent sides of a parallelogram are in the ratio 3:7 and the perimeter is 100 cm . Find the sides of the parallelogram .
To Find :-
- The sides of parallelogram .
Solution :-
# Consider a parallelogram ABCD in which ,
- AB = CD &
- BC = AD
- BC : AB = 3 : 7
Or
- CD : AD = 3 : 7
Let the ratios be 3x & 7x
so ,
- AB = CD = 7x
- BC = AD = 3x
As we know ,
So , Here ,
So ,
Sides of the parallelogram would be :
- AB = CD = 7×5 cm = 35 cm .
- BC = AD = 3×5 cm = 15 cm .
NOTE : The opposite sides of a parallelogram are equal in length and are parallel .