Math, asked by partu4857, 9 months ago

The adjacent sides of a rectangle are (3x) 2-2xy+(5y) 2 and (2x) 2 +(5xy) - (3y) 2 find it's area

Answers

Answered by THRISHALDOMA
4

Answer:

(3x)^2 - 2xy + (5y)^2 = 9x^2 - 2xy + 25y^2

(2x)^2 + 5xy - (3y)^2 = 4x^2 + 5xy - 9y^2

Step-by-step explanation:

(9x^2 - 2xy + 25y^2) (4x^2 + 5xy - 9y^2)

9x^2 (4x^2 + 5xy - 9y^2) - 2xy (4x^2 + 5xy - 9y^2) + 25y^2 (4x^2 + 5xy - 9y^2)

36x^4 + 45x^3 y - 81x^2 y^2 - 8x^3 y - 10 x^2 y^2 + 18x y^2 + 100x^2 y^2 + 125 x y^3 - 225y^4

(2x)^4 + 45x^3 y - (9xy)^2 - (2x)^3 y - 10(xy)^2 + 18xy^2 + (10xy)^2 + (5y)^3 x - 225y^4

I hope this will help you !

Answered by ashokbaskey1999
0

Answer:

The adjacent sides of a rectangle are 3x2 – 2xy + 5y2 and 2x2 + 5xy – 3y2

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Find the area of the rectangle.

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