Question

What must be subtracted from 2p2 + 3p + 1 to get 5p2 – 2p + 9

Answer 1

Answer:

-3p²+5p-8 should be subtracted from 2p²+3p+1 to get 5p²-2p+9

Step-by-step explanation:

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Answer 2

Answer:

x = 5p + 3p² +8

Step-by-step explanation:

Let the subtracted number be x

2p² + 3p + 1 - x = 5p² - 2p + 9

2p² + 3p + 1 - x = 5p² - 2p + 9- x = 5p² - 2p + 9 - 2p² - 3p - 1

2p² + 3p + 1 - x = 5p² - 2p + 9- x = 5p² - 2p + 9 - 2p² - 3p - 1- x = 3p²- 5p + 8

2p² + 3p + 1 - x = 5p² - 2p + 9- x = 5p² - 2p + 9 - 2p² - 3p - 1- x = 3p²- 5p + 8- x = - 5p + 3p² +8

2p² + 3p + 1 - x = 5p² - 2p + 9- x = 5p² - 2p + 9 - 2p² - 3p - 1- x = 3p²- 5p + 8- x = - 5p + 3p² +8x = 5p + 3p² +8

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