Question

the adjacent sides of parallelogram are 36 cm and 27 cm in length if the prendicular distance between the shorter sides is 12 cm find the distance between the longer sides​

Answer 1

Answer:

Area of a parallelogram = base * hright.(perpendicular distance between the sides)

In thr given parallelogram :

Area = 27 cm * 12 cm (perpendicular distance between shorter sides)

Let us consider the perpendicular distance between the longet sides be = h

equating the area.

27 * 12 = 36 * h

=》 h = 9 cm

Ans)) 9 cm

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Answer 2

Step-by-step explanation:

$\setlength{\unitlength}{1.5cm}\begin{picture}(8,2)\linethickness{0.4mm}\put(8.6,3){\large\tt{A}}\put(7.7,0.9){\large\tt{B}}\put(9.5,0.7){\sf{\large{36 cm}}}\put(11.1,0.9){\large\tt{C}}\put(8,1){\line(1,0){3}}\qbezier(11,1)(11.5,2)(12,3)\put(9,3){\line(3,0){3}}\put(9.1,2){\sf{\large{12 cm}}}\put(9,1){\line(0,1){2}}\qbezier(8,1)(8.5,2)(9,3)\qbezier(11.5,2)(11.5,2)(9,3)\put(12.1,3){\large\tt{D}}\put(11.5,1.6){\sf{\large{27 cm}}}\put(11.65,2){\large\tt{M}}\put(8.9,0.7){\large\tt{N}}\end{picture}$

• Adjacent Sides of Parallelogram are 36 cm and 27 cm

• Distance between Shorter Sides = 12 cm

• Distance between Longer Sides = ?

$\bigstar\:\boxed{\sf Area\:of\:Paralleogram=Base \times Height}$

⠀

$\underline{\bigstar\:\textsf{According to the given Question :}}$

$:\implies\sf Area\:of\:\parallel\: _{with \:base\:BC}=Area\:of\:\parallel\:_{with \:base\:CD}\\\\\\:\implies\sf Base \times Height = Base \times Height\\\\\\:\implies\sf BC \times AN=CD \times AM\\\\\\:\implies\sf 36 \times 12 =27 \times AM\\\\\\:\implies\sf \dfrac{36 \times 12}{27} = AM\\\\\\:\implies\sf 4 \times 4 = AM\\\\\\:\implies\underline{\boxed{\sf AM = 16\:cm}}$

⠀

$\therefore\:\underline{\textsf{Distance between longer sides is \textbf{16 cm}}}.$