Question

the adjacent sides of rectangle are 3x-5y-4z and x-3y+5z. find its perimeter

Answer 1

Hope it helps....

Length=3x-5y-4z and Breadth=x-3y+5z....

So, perimeter of rectangle
=2(length+breadth)units
=2{(3x-5y-4z)+(x-3y+5z)}
=2(3x-5y-4z+x-3y+5z)
=2(3x+x-5y-3y-4z+5z)
=2(4x-8y+z)
=8x-16y+2z
Therefore, the perimeter of the rectangle is 8x-16y+2z.

Answer 2

Answer:

Hey Mate here's your answer..