Question

The adjacent sides of rectangle are 5x^2-3y^2 and x^2+2xy. Find the perimeter
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Answer 1

Step-by-step explanation:

Given adjacent sides of a rectangle are $$5x^2-3y^2$$ and $$x^2+2xy$$

we know that the perimeter of a rectangle with adjacent sides $$a$$ and $$b$$ is $$2 \times (a+b)$$

Perimeter$$=2((5x^2-3y^2)+(x^2+2xy))$$

$$=2(6x^2-3y^2+2xy)$$

$$=12x^2-6y^2+4xy$$

$$\therefore Perimeter=12x^2-6y^2+4xy$$