the adjoining figure is made up of a triangle inscribed in a semicircle in which AB =20 cm , BC=15 cm and angle b is a right angle. Find the area of shaded region
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Since ∆ABC is right angled at B ,
AC² = AB² + BC² = 15² + 20² = 25²
AC = 25cm = 2r
r = 12.5cm
Area of semicircle : πr²/2 = 245.3 cm²
Area of ∆ABC : 1/2 * 20 * 15 = 150 cm²
Area of shaded region : 245.3 - 150 = 95.3 cm²
AC² = AB² + BC² = 15² + 20² = 25²
AC = 25cm = 2r
r = 12.5cm
Area of semicircle : πr²/2 = 245.3 cm²
Area of ∆ABC : 1/2 * 20 * 15 = 150 cm²
Area of shaded region : 245.3 - 150 = 95.3 cm²
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