Question

the adjoining the figure is made two triangle:triangle abcd​

Answer 1

Given: AL⊥BC and DM⊥BC

In △ALO and △MOD

∠AOL=∠MOD (Vertically opposite angles)

∠ALO=∠DMO (Each 90∘)

∠LAO=∠MDO (Third angle)

Thus, △ALO∼△DMO (AAA rule)

Hence, ODAO=DMAL (Corresponding sides)...(I)

Area of triangle = 21base×height

A(△DBC)A(△ABC)=21BC×DM21BC×AL

A(△DBC)A(△ABC)=DMAL

A(△DBC)A(△ABC)=ODAO (from I)

Answer 2

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Given: AL⊥BC and DM⊥BC

In △ALO and △MOD

∠AOL=∠MOD (Vertically opposite angles)

∠ALO=∠DMO (Each 90∘)

∠LAO=∠MDO (Third angle)

Thus, △ALO∼△DMO (AAA rule)

Hence, ODAO=DMAL (Corresponding sides)...(I)

Area of triangle = 21base×height

A(△DBC)A(△ABC)=21BC×DM21BC×AL

A(△DBC)A(△ABC)=DMAL

A(△DBC)A(△ABC)=ODAO (from I)

HOPE SO IT WILL HELP...