Question

the aerage velocity of an ideal gas molecules at 27°c is .3m/s.the average velocity at 927°c will

Answer 1

27°C = 300 K
927°C = 1200 K

Average velocity ∝ sqrt(Absolute Temperature)

v1 / v2 = sqrt(T1 / T2)
0.3 / v = sqrt(300 / 1200)
0.3 / v = 1 / 2
v = 0.6 m/s

Average velocity at 927°C is 0.6 m/s

Answer 2

Answer:

Explanation:27°C = 300 K

927°C = 1200 K

Average velocity ∝ sqrt(Absolute Temperature)

v1 / v2 = sqrt(T1 / T2)

0.3 / v = sqrt(300 / 1200)

0.3 / v = 1 / 2

v = 0.6 m/s

Average velocity at 927°C is 0.6 m/s