Question

The age of a father is 3 years more than three times the age of his son. Three years hence father's age will exceed twice the age of his son by 13 years. What will be their ages after 4 years.

Answer 1

Let initial age of son be x.
Initial age of father = 3x + 3                  -----1
After 3 years, age of son = x+3
Age of father after 3 years = 2(x+3) + 13  -----2
From 1 and 2,
3x + 3 +3 = 2(x+3) + 13
3x + 6 = 2x + 19
x = 13
So, Father's initial age = 3x + 3 = 42
Age of son after 4 years = 13 + 4 = 17
Age of father after 4 years = 42 + 4 = 46

Answer 2

Given that :

• The age of the father is 3 years more than three times the age of the son.
• Three years hence, father's age will exceed twice the age of the son by 13 years.

To Find :

• What will be their ages after 4 years?

Let us assume :

• The age of the son be x
• Father's age = 3x + 3

Three years hence :

• Son's age = x + 3
• Father's age = 3x + 3 + 3

According to the question :

Father's age = 2(Son's age) + 13

→ 3x + 3 + 3 = 2(x + 3) + 13

→ 3x + 6 = 2x + 6 + 13

→ 3x – 2x = 6 + 13 – 6

→ x = 13

There present ages :

• Son's age = x = 13 yrs
• Father's age = 3x + 3 = 3(13)+3 = 42 years.

Ages after 4 years :

• Son's age = 13 + 4 = 17 years
• Father's age = 42 + 4 = 46 years

Hence,

• After four years, the age of son will be 17 years and father's age will be 46 years
• Son's age = 17 years
• Father's age = 46 years.

Hope it helps ! :))