Question

find the area of sector of a cicrle with radius 4cm &of angle 60 degree
give ans full & decribe it . in steps

Answer 1

we have area of sector
Ф/360×πr²
60/360×3.14×4×4
1/6×3.14×4×4
=8.7333333 -------------------ans

Answer 2

Area of a sector with angle α and radius r is given by 

$A= \frac{ \alpha }{360} * \pi r^2$

Here α = 60⁰, r = 4cm

$A= \frac{60}{360} * \pi r^2\\ \\A= \frac{1}{6} * \frac{22}{7} *4^2\\ \\A=\boxed{8.38\ cm^2}$