Question

The age of a father is 6 times the age of his son.20 years from now father's age will be

Answer 1

suppose present age=x. father = x+3

so
after 20 years =x+20 , x+23

Answer 2

solutions :-

Let the present age of son be x

Let the present age of his father be 6x

After 20 years, age of son = x + 20

After 20 years, age of his father = 6x + 20

In 20 years, father will be twice the age of son = 2(x + 20) = 2x + 40


According to the question, 

6x + 20 = 2x + 40

6x - 2x = 40 - 20

4x = 20

x = \dfrac{20}{4}420​ 

x = 5 



Present age of son => (6x + 20 )years

=> 50 years ✔