Question

The age of a father is twice that of his son's present age.After 5yr the sum of their ages will be 85.how old are they now​

Answer 1

Answer:

age of son = x = 25 years

age of son = x = 25 yearsage of father = 2x = 50 years

Step-by-step explanation:

let present age of son = x

father's present age = 2x

given that

{ (x+5) + (2x+5) } = 85

=> 3x + 10 = 85

=> 3x = 85-10

=> 3x = 75

=> x = 75/3

=> x = 25

age of son = x = 25 years

age of son = x = 25 yearsage of father = 2x = 50 years

Answer 2

Answer:

Father = 50, Son = 25

Step-by-step explanation:

Present :

F = 2S .........(1)

After 5 years:

F + 5 + S + 5 = 85

F + S = 75

2S + S = 75 .........(From 1)

3S = 75

S = 25

Substitute in (1)

F = 2 × 25

F = 50