The age of a father is twice the age of square of the age of his son, eight years hence, the age of the father will be 4 years more than 3 times the age of the son. Find their present ages ?
Answers
Given
- Age of father = 2(square of age of his son)
- After 8 years, father age = 4 years more than 3 times(son age)
Solution
- Let the present age of son be x
- Let the present age of father be 2x²
According to the question :-
- 2x² + 8 = 3(x + 8) + 4
- 2x² + 8 = 3x + 24 + 4
- 2x² + 8 - 3x - 28 = 0
- 2x² - 3x - 20 = 0
- 2x² - 8x + 5x - 20 = 0
- 2x(x - 4) + 5(x - 4) = 0
- x - 4 = 0 or 2x + 5 = 0
- x = 4 or x = -5/2
Since, the value of x cannot be negative, we consider the value of x to be 4
Son's age
- x = 4 years
Father's age
- 2x² = 2(4)²
- 2(16) = 32 years
Hence, the present age of son is 4 years and that of father is 32 years.
Answer:
Step-by-step explanation:
Given
Age of father = 2(square of age of his son)
After 8 years, father age = 4 years more than 3 times(son age)
Solution
Let the present age of son be x
Let the present age of father be 2x²
According to the question :-
2x² + 8 = 3(x + 8) + 4
2x² + 8 = 3x + 24 + 4
2x² + 8 - 3x - 28 = 0
2x² - 3x - 20 = 0
2x² - 8x + 5x - 20 = 0
2x(x - 4) + 5(x - 4) = 0
x - 4 = 0 or 2x + 5 = 0
x = 4 or x = -5/2
Since, the value of x cannot be negative, we consider the value of x to be 4
Son's age
x = 4 years
Father's age
2x² = 2(4)²
2(16) = 32 years
Hence, the present age of son is 4 years and that of father is 32 years.