The age of a father is twice the square of the age of his son.Eight years hence, the age of the father will be 4 years more than three times the age of his son. find their present ages.
Answers
Answer:
Step-by-step explanation:
Let the present age of son be x years
Present age of his father be 2x² years
Age of son after 8 years =(x+8) years
Age of his father after 8 years years= (2x²+8) years
Given age of man will be 4 years more than 3 times his sons age.
Hence , 2x²+8=3(x+8)+4
→ 2x²+8=3x+28
→ 2x²-3x-20=0
→ 2x²-8x+5x-20=0
→ 2x(x-4)+5(x-4)=0
→ (x-4)(2x+5)=0
x-4=0 or 2x+5=0
∴ x=4 or x= -5/2
Hence x=4 since age cannot be negative
→ 2x²=2(4)²=32
Therefore present age of son is 4 years and present age of his father is 32 years.
Answer:
Step-by-step explanation:
Solution :-
Let x be the present age of son.
And the present age of man is 2x² years.
8 years hence :-
Age of the son = x + 8 years.
Age of the man = 2x² + 8 years.
According to the Question,
⇒ (2x² + 8) = 3(x + 8) + 4
⇒ 2x² - 3x - 20 = 0
⇒ 2x² - 8x + 5x - 20 = 0
⇒ 2x(x - 4) + 5(x - 4) = 0
⇒ (x - 4) (2x + 5) = 0
⇒ x - 4 = 0 or 2x + 5 = 0
⇒ x = 4, - 5/2 (As x can't be negative)
⇒ x = 4
Son's present age = x = 4 years.
Man's present age = 2x² = 2(4)² = 2(16) = 32 years.
Hence, the present age of son and man is 4 years and 32 years.
Similar Question :- [Click on the links]
https://brainly.in/question/8377608
https://brainly.in/question/4938888
https://brainly.in/question/12999186
https://brainly.in/question/12142970
https://brainly.in/question/283211