Question

the age of a is 2/3 that of B. 5 years old A's age was 3/5 of B's age . what are their present ages?​

Answer 1

Explanation:

let current age of B be x

then current age of A according to question will be y= 2x/3

5year before

age of B must have been x-5

n age of A was y-5= 3(x-5)/5

solving both the equations we get

y-(y-5)= 2x/3- 3x/5+ 3

current ages

therefore age of B= 30 yrs

and age of A=20 yrs

Answer 2

Answer:

Present age of A $= x years = 20years$

Present age of B = $y years= 30years$

#SPJ2

Explanation:

Let the present age of A $= x years$

Let the present age of B = $y years$

According to given condition,

Age of A is $\frac{2}{3}$ that of age of B .

                     $x = \frac{2}{3} y$                                             1

• Five years ago,

Age of B $= (x-5) years$

Age of A $= (y-5)years$

According to given condition,

Age of  A was $\frac{3}{5}$ age of B.

$y-5= \frac{3(x-5)}{5}$                                                           2

Solving equations 1 and 2 , to get value of $x$ and $y$,

$x = 20 \\y= 30$

Therefore,

The present age of A $= x years = 20years$

The present age of B = $y years= 30years$

#SPJ2