Math, asked by salmanahmed19, 1 year ago

The age of A is 5 years more than of B , 5 years ago ,the ratio of their ages was 3:2 . Find their present ages.

Answers

Answered by digi18
117
Let the age of A = x+5
age of B = x

5 year ago age was

(x+5)-5/x-5 = 3/2

x/ x-5 = 3/2

2x = 3x - 15

x = 15

Age of B = 15
Age of A = 15+5 = 20

salmanahmed19: thank you
Answered by abhi569
31

let the age of B is x and then age of A is (x+5)

before five years

Age of A was x - 5 and and age of B was x + 5 -5 =x

Ratio was 3 : 2

= > x/(x - 5) = 3/2

= > 2x = 3x - 15

= > x = 15

then present age of A is 15 + 5 = 20 and present age of B is x = 15 years


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